numpy pandas 学习记录

2056天前 · 分享 · 740次阅读

import numpy as np
import pandas as pd
from pandas import Series, DataFrame
s1 = Series([1,2,3],index=['A','B','C'])
s1
A    1
B    2
C    3
dtype: int64



s2 = Series([4,5,6,7],index=['B','C','D','E'])
s2
B    4
C    5
D    6
E    7
dtype: int64



s1 + s2
A    NaN
B    6.0
C    8.0
D    NaN
E    NaN
dtype: float64


对应index相加,对不上的就是NaN

DataFrame的运算

df_a = DataFrame(np.arange(4).reshape(2,2),index=['A','B'],columns=['北京','上海'])
df_b = DataFrame(np.arange(9).reshape(3,3),index=['A','B','C'],columns=['北京','上海','广州'])
df_a
北京 上海
A 0 1
B 2 3
df_b
北京 上海 广州
A 0 1 2
B 3 4 5
C 6 7 8
df_a + df_b
上海 北京 广州
A 2.0 0.0 NaN
B 7.0 5.0 NaN
C NaN NaN NaN
类似的,index和columns对应的部分可以相加,否则为NaN
df_c = DataFrame([[1,2,3],[4,5,np.nan],[7,8,9]],index=['A','B','C'],columns=['c1','c2','c3'])
df_c
c1 c2 c3
A 1 2 3.0
B 4 5 NaN
C 7 8 9.0
df_c.sum()
c1    12.0
c2    15.0
c3    12.0
dtype: float64



df_c.sum(axis = 1)
A     6.0
B     9.0
C    24.0
dtype: float64



type(df_c.sum())
pandas.core.series.Series


DataFrame中求和的时候会忽略NaN
axis = 1 可以指定行的计算
df_c.describe()
c1 c2 c3
count 3.0 3.0 2.000000
mean 4.0 5.0 6.000000
std 3.0 3.0 4.242641
min 1.0 2.0 3.000000
25% 2.5 3.5 4.500000
50% 4.0 5.0 6.000000
75% 5.5 6.5 7.500000
max 7.0 8.0 9.000000
s1.index
Index(['A', 'B', 'C'], dtype='object')



s1.sort_values()#按value升序
A    1
B    2
C    3
dtype: int64



s1.sort_values(ascending=False)#按value降序
C    3
B    2
A    1
dtype: int64



s1.sort_index(ascending=False)#按index降序
C    3
B    2
A    1
dtype: int64



df_d = DataFrame(np.random.randn(35).reshape(7,5),columns=['A','B','C','D','E'])
df_d
A B C D E
0 -0.694245 -0.302792 0.667865 0.447782 -0.413812
1 -0.502081 -1.849090 1.885715 -1.117864 0.406936
2 0.384877 0.076701 -1.052755 -0.709675 0.272562
3 -1.194740 -0.518320 -0.139549 -0.745238 1.270952
4 -1.266443 -1.163004 -0.644873 -0.333446 0.349508
5 -0.695937 -0.589887 1.475200 0.278659 2.207159
6 -0.712247 0.171372 0.268192 0.138490 0.604858
df_d.sort_values('A',ascending=False)#按A列降序
A B C D E
2 0.384877 0.076701 -1.052755 -0.709675 0.272562
1 -0.502081 -1.849090 1.885715 -1.117864 0.406936
0 -0.694245 -0.302792 0.667865 0.447782 -0.413812
5 -0.695937 -0.589887 1.475200 0.278659 2.207159
6 -0.712247 0.171372 0.268192 0.138490 0.604858
3 -1.194740 -0.518320 -0.139549 -0.745238 1.270952
4 -1.266443 -1.163004 -0.644873 -0.333446 0.349508
df_d.sort_index(ascending=False)#按index降序
A B C D E
6 -0.712247 0.171372 0.268192 0.138490 0.604858
5 -0.695937 -0.589887 1.475200 0.278659 2.207159
4 -1.266443 -1.163004 -0.644873 -0.333446 0.349508
3 -1.194740 -0.518320 -0.139549 -0.745238 1.270952
2 0.384877 0.076701 -1.052755 -0.709675 0.272562
1 -0.502081 -1.849090 1.885715 -1.117864 0.406936
0 -0.694245 -0.302792 0.667865 0.447782 -0.413812

所谓课后练习 ——> 将一个已有csv文件中的三列提取出来,按其中一项降序排列,要求用一行完成(真是。。)。

import pandas as pd
csv_file = open("E:/Python3数据科学入门与实战/project/o25mso/homework/movie_metadata.csv","r",encoding="utf-8")
read_csv_in = pd.read_csv(csv_file)
df = read_csv_in[['imdb_score','director_name','movie_title']].sort_values('imdb_score',ascending=False)
df.to_csv('new_imdb.csv')
#pd.read_csv(open("E:/Python3数据科学入门与实战/project/o25mso/homework/movie_metadata.csv"))[['imdb_score','director_name','movie_title']].sort_values('imdb_score',ascending=False)
!ls
csv_practice.ipynb
demo.ipynb
new_imdb.csv
practice-2018-08-11.ipynb

有中文路径时通过open("filename","r",encoding="utf-8")读进来,
再用pandas.read_csv()读。注意用utf-8读取否则会出现问题。
这样做好处主要是允许路径有中文
df.head()
imdb_score director_name movie_title
2765 9.5 John Blanchard Towering Inferno
1937 9.3 Frank Darabont The Shawshank Redemption
3466 9.2 Francis Ford Coppola The Godfather
4409 9.1 John Stockwell Kickboxer: Vengeance
2824 9.1 NaN Dekalog
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pandas numpy

最后修改于2056天前

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